Bourbaki

Exercise 11, § 2

Tag 01L3, permanent. Cite it as [Bourbaki, Tag 01L3].

Lie Groups and Lie Algebras, IX, 393

Let G be a compact Lie group. A subgroup S of G is said to be of type (C) if it is equal to the closure of a cyclic subgroup that is of finite index in its normalizer.

a) Let S be a subgroup of type (C); show that S0S_0 is a maximal torus of G0G_0, and that S is the direct product of S0S_0 and a finite cyclic subgroup.

b) Prove that every element gg of G is contained in a subgroup of type (C) (consider the group generated by gg and a maximal torus of Z(g)0Z(g)_0).

11^{11}For a proof of this theorem, see for example S. LEFSCHETZ, Intersections and

transformations of complexes and manifolds, Trans. Amer. Math. Soc. 28 (1926),

pp. 1-49. c) Let S be a subgroup of type (C), and ss an element of S whose set of powers is dense in S. Show that every element of sG0sG_0 is conjugate under Int(G0_0) to an element of sS0sS_0 (use the method of Exerc. 10).

d) Denote by p:G→G/G0p: G\rightarrow G/G_0 the quotient map. Show that the map S→p(S)S \rightarrow p(S) induces a bijection from the set of conjugacy classes of subgroups of G of type (C) to the set of conjugacy classes of cyclic subgroups of G/G0G/G_0.

e) Let S be a subgroup of G of type (C); denote by SρS_{\rho} the set of elements of S whose class in S/S0S/S_0 generates S/S0S/S_0. Show that two elements of SρS_{\rho} that are conjugate in G are conjugate in NG(S)N_G(S).

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