Bourbaki

Definition 11

Tag 03HU, permanent. Cite it as [Bourbaki, Tag 03HU].

Theory of Sets, chapter II, § 3. Correspondences

Let ff be an injective (resp. surjective) mapping of A into B. Any mapping rr (resp. ss) of B into A such that r∘fr \circ f (resp. f∘sf \circ s) is the identity mapping of A (resp. B) is called a retraction (resp. section) of ff.

Instead of retraction (resp. section) the phrase left-inverse (resp. right-inverse) is sometimes used.

¶ If ff is injective (resp. surjective) and if rr (resp. ss) is a retraction (resp. section) of ff, then ff is a section (resp. retraction) of rr (resp. ss). Hence a retraction is surjective and a section is injective.

¶ If ff is surjective and if ss, s′s' are two sections of ff such that s(B)=s′(B)s(\mathrm{B}) = s'(\mathrm{B}), then s=s′s = s'; for if x∈Bx \in \mathrm{B}, there exists y∈By \in \mathrm{B} such that s(x)=s′(y)s(x) = s'(y), and we have x=f(s(x))=f(s′(y))=yx = f(s(x)) = f(s'(y)) = y, so that s(x)=s′(x)s(x) = s'(x) and consequently s=s′s = s'. Thus a section ss is uniquely determined by the set s(B)s(\mathrm{B}). By abuse of language, the set s(B)s(\mathrm{B}) is sometimes called a section of ff.

Bourbaki sets the proof directly after the statement, and the corpus does not separate them, so what is above is the statement and its proof together.

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Transcribed from the printed edition, 2004, Springer. Not translated.