Bourbaki

Proposition 12

Tag 0438, permanent. Cite it as [Bourbaki, Tag 0438].

Commutative Algebra, chapter I, § 2. Flat modules

Let A, B be commutative rings, φ\varphi a homomorphism of A to B, E1,E2,E3E_1, E_2, E_3 three A-modules, f:E1×E→E3f : E_1 \times E \to E_3 an A-bilinear mapping and

fB:E1(B)×E2(B)→E3(B) f_B : E_{1(B)} \times E_{2(B)} \to E_{3(B)}

its extension. Consider a submodule F2F_2 of E2E_2, a submodule F3F_3 of E3E_3, and denote by T the submodule of E1E_1 consisting of those x1∈E1x_1 \in E_1 such that f(x1,x2)∈Ff(x_1, x_2) \in F, for all x2∈Fx_2 \in F. Suppose that B is a flat A-module and that F2F_2 is finitely generated. Then T(B)T_{(B)} is the set of those x1′∈E1(B)x'_1 \in E_{1(B)} such that fB(x1′,x2′)∈F3(B)f_B(x'_1, x'_2) \in F_{3(B)} for all x2′∈F2(B)x'_2 \in F_{2(B)}.

Let pp be the canonical surjection E3→E3/F3E_3 \to E_3/F_3; with each x1∈E1x_1 \in E_1 we associate the A-linear mapping x2↦p(f(x1,x2))x_2 \mapsto p(f(x_1, x_2)) of F2F_2 to E3/F3E_3/F_3, which we denote by g(x1)g(x_1); then gg is an A-homomorphism of E1E_1 to HomA(F2,E3/F3)\mathrm{Hom}_A(F_2, E_3/F_3) and the kernel of gg is precisely T. Since B is a flat A-module, we have the exact sequence

0⟶T(B)⟶E1(B)→1⊗g(HomA(F2,E3/F3))(B) 0 \longrightarrow T_{(B)} \longrightarrow E_{1(B)} \xrightarrow{1 \otimes g} (\mathrm{Hom}_A(F_2, E_3/F_3))_{(B)}

(no. 3, Proposition 1). By Proposition 11 the canonical homomorphism

ω:(HomA(F2,E3/F3))(B)→HomB(F2(B),(E3/F3)(B)) \omega : (\mathrm{Hom}_A(F_2, E_3/F_3))_{(B)} \to \mathrm{Hom}_B(F_{2(B)}, (E_3/F_3)_{(B)})

is injective. On the other hand, as B is a flat A-module, (E3/F3)(B)(E_3/F_3)_{(B)} is canonically identified with E3(B)/F3(B)E_{3(B)}/F_{3(B)}; taking the composition of ω\omega with 1⊗g1 \otimes g, we obtain a homomorphism uu for which the sequence!

0⟶T(B)⟶E1(B)→uHomB(F2(B),E3(B)/F3(B)) 0 \longrightarrow T_{(B)} \longrightarrow E_{1(B)} \xrightarrow{u} \mathrm{Hom}_B(F_{2(B)}, E_{3(B)}/F_{3(B)})

is exact. It follows immediately from the definitions that u(x1′)u(x'_1), where

x1′=1⊗x1∈E1(B), x'_1 = 1 \otimes x_1 \in E_{1(B)},

is the linear mapping which maps each x2′∈F2(B)x'_2 \in F_{2(B)} to the class mod. F3(B)F_{3(B)} of fB(x1′,x2′)f_B(x'_1, x'_2); by linearity this is also true for all x1′∈E1(B)x'_1 \in E_{1(B)}; since the kernel of uu is T(B)T_{(B)}, the proposition is proved.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.