Lemma 3
Tag 04F0, permanent. Cite it as [Bourbaki, Tag 04F0].
Commutative Algebra, chapter III, § 2. General results on filtered rings and modules
Let be a complete Hausdorf topological ring, in which there exists a fundamental system of neighbourhoods of 0 consisting of additive subgroups of . (i) For all such that , is invertible in and its inverse is equal to . (ii) Let be a two-sided ideal of such that for all . For an element y of to be invertible, it is necessary and sufficient that its class mod. a be invertible in ; in particular a is contained in the Jacobson radical of .
(i) As
it all amounts to proving that the series with general term is convergent in ; now, by hypothesis, for every neighbourhood of 0 in , there exists an integer such that for all . We conclude that
for all and our assertion then follows from Cauchy's criterion (General Topology, Chapter III, § 5, no. 2, Theorem 1).
(ii) Suppose that there exists such that (mod. a) and (mod. a). The hypothesis on a implies, by (i), that and are invertible in and hence is invertible in . In particular, every is such that is invertible in and, as a is a two-sided ideal of , it is contained in the Jacobson radical of (Algebra, Chapter VIII, § 6, no. 3, Theorem 1).
Having established this lemma, it is sufficient to apply it to the topological ring and the ideal , as, for all , and the sequence therefore tends to 0.
If we take , every maximal ideal of is of the form where is prime. The ring of -adic numbers is then a local ring of which is the maximal ideal (Corollary 2 to Proposition 16) and whose residue field is isomorphic to , and with the -adic topology is identified with a topological subring of , containing .
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.