Bourbaki

Proposition 7

Tag 04I6, permanent. Cite it as [Bourbaki, Tag 04I6].

Commutative Algebra, chapter III, § 4. Lifting in complete rings

Let AA be a ring and mm an ideal of AA such that the ordered pair (A,m)(A, m) satisfies Hensel's conditions. Let f=(f1,…,fn)f = (f_1, \ldots, f_n) be a system without constant term of series in A[[X1,…,Xn]]A[[X_1, \ldots, X_n]] such that Jf(0)J_f(0) is invertible in AA. Then, for all x∈mxnx \in m^{x^n}, f(x)∈mxnf(x) \in m^{x^n} and x↦f(x)x \mapsto f(x) is a bijection of mxnm^{x^n} onto itself, the inverse bijection being x↦g(x)x \mapsto g(x), where gg is given by relation (16) in no. 4.

The fact that f(x)∈mxnf(x) \in m^{x^n} is obvious when theft are polynomials and follows in the general case from Proposition 6 and the fact that mm is closed in AA. The other assertions of the proposition are then immediate consequences of (16), (17) and (18).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.