Bourbaki

Proposition 6

Tag 04NA, permanent. Cite it as [Bourbaki, Tag 04NA].

Commutative Algebra, chapter V, § 1. Notion of an integral element

Let AA be a ring, BB a (commutative)A-algebra and CC a (not necessarily commutative)B-algebra. If BB is integral over AA and CC is integral over BB, then CC is integral over AA.

It is sufficient to verify that every x∈Cx \in C is integral over AA. By hypothesis there exists a monic polynomial Xn+b1Xn−1+⋯+bX^n + b_1 X^{n-1} + \cdots + b, with coefficients in BB with xx as a root; then xx is integral over B′=A[b1,…,bn]B' = A[b_1, \ldots, b_n] and B′[x]B'[x] is therefore a finitely generated B-module. But as BB is integral over AA, B′B' is a finitely generated A-module (Proposition 4); we conclude that B'[x] is also a finitely generated A-module (Algebra, Chapter 11, § 1, no. 13, Proposition 25) and therefore x is integral over A.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.