Bourbaki

Proposition 11

Tag 04NN, permanent. Cite it as [Bourbaki, Tag 04NN].

Commutative Algebra, chapter V, § 1. Notion of an integral element

Let A be a ring, R an A-algebra and P and Q monic polynomials in R[X]. If the coefficients of PQ are integral over A, the coefficients of P and Q are integral over A.

By a double application of Lemma 2, we see that there exists a ring R' containing R and families of elements (ai)1≤i≤m,(bj)1≤j≤n(a_i)_{1 \leq i \leq m}, (b_j)_{1 \leq j \leq n} of R' such that in R′[X]R'[X]

P(X)=∏i=1∞(X−ai),Q(X)=∏j=1n(X−bj); P(X) = \prod_{i=1}^\infty (X - a_i), \quad Q(X) = \prod_{j=1}^n (X - b_j);
the coefficients of P Q belong to the integral closure A′A' of A in R' and hence (no. 2, Proposition 7) the elements a,(1≤i≤m)a, (1 \leq i \leq m) and b,(1≤j≤n)b, (1 \leq j \leq n) belong to A. It follows that the coefficientsof P and Qare integral over A (no. 1, Corollary 1 to Proposition 4).

Let A be an integral domain, K its field of fractions and K' a K-algebra (not necessarily commutative). Given an element x∈K′x \in K' algebraic over K, the polynomials P∈K[X]P \in K[X] such that P(x)=0P(x) = 0 form an ideal a≠0a \neq 0 of K[X]K[X], necessarily principal (Algebra, Chapter IV, § 1, no. 5, Proposition 7). There exists a unique monic polynomial which generates a; generalizing the terminology introduced in Algebra, Chapter V, § 3, no. 1, Definition 3, this monic polynomial will be called the minimal polynomial of x over K.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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