Corollary 3
Tag 04PP, permanent. Cite it as [Bourbaki, Tag 04PP].
Commutative Algebra, chapter V, § 2. The lift of prime ideals
Let be a ring homomorphism such that is integral over and a maximal ideal of and suppose that there are in only a finite number of distinct maximal ideals () lying above . Let be the saturation of with respect to (Chapter II, § 2, no. 4). Then: (i) In the ring the divisors of zero are the elements of and they are nilpotent (). (ii) . (iii) The canonical homomorphism is bijective.
For a prime ideal of to contain , it is necessary and sufficient that its inverse image under contain and hence that it lie above , since is maximal in ; the are therefore the only prime ideals of containing (Proposition 1) and therefore is the radical of (Chapter II, § 2, no. 6, Corollary 1 to Proposition 13). By definition of , the class mod. of an element of is not a divisor of 0 in ; on the other hand, as the are distinct maximal ideals, for every index there exists an element belonging to and not to (Chapter II, § 1, no. 1, Proposition 4): then, for all , hence the class mod. of is nilpotent and, as that of is not a divisor of 0, we conclude that the class of is nilpotent; in other words is the radical of , which proves (i). It follows that the are relatively prime in pairs (Chapter II, § 1, no. 1, Proposition 3); (iii) will therefore be a consequence of (ii), taking account of Chapter II, § 1, no. 2, Proposition 5. To establish (ii), we note that in the ring the are the only maximal ideals and is the saturation of (0) with respect to (Chapter 11, § 2, no. 4); we may therefore restrict our attention to the case ; the assertion of (ii) then follows from Chapter II, § 3, no. 3, Corollary 2 to Theorem 1.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
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