Remark
Tag 056Y, permanent. Cite it as [Bourbaki, Tag 056Y].
Algebra, chapter I, § 2. Identity element; cancellable elements; invertible elements
Let E be a monoid and x an element of E. If x is left invertible it is left cancellable; for, if is a left inverse of , then
and is injective. In particular, if x is left invertible, the left and right translations by x are bijective. Conversely, suppose that is bijective; there exists such that ; then and hence , so that x is invertible. We see similarly that if is bijective, x is invertible.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
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Cites
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