Bourbaki

Theorem 1

Tag 05BJ, permanent. Cite it as [Bourbaki, Tag 05BJ].

Algebra, chapter I, § 5. Groups operating on a set

Let G be a group. (a) Every homogeneous G-set is isomorphic to a homogeneous G-set of the form G/H where H is a subgroup of G. (b) Let H and H' be two subgroups of G. The G-sets G/H and G/H' are isomorphic if and only if H and H' are conjugate.

As a homogeneous G-set is non-empty, assertion (a) follows from Proposition 6. We show (b). Let f:G/H→G/H′f : G/H \to G/H' be a G-set isomorphism. The subgroup H is the stabilizer of H and hence, by transport of structure, the stabilizer of an element of G/H′G/H'. The subgroups HH and H′H' are therefore conjugate (no. 2, Proposition 2). If H′=αHα−1H' = \alpha H \alpha^{-1}, H′H' is the stabilizer of the element α.H\alpha . H of G/HG/H (no. 2, Proposition 2) and hence G/H′G/H' is isomorphic to G/HG/H (Proposition 6).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

Transcribed from the printed edition, 1998, Springer. Not translated.