Bourbaki

Definition 7

Tag 05DM, permanent. Cite it as [Bourbaki, Tag 05DM].

Algebra, chapter I, § 6. Extensions, solvable groups, nilpotent groups

Let G be a group. The derived series of G is the series (D^n(G)){n \in \mathbf{N}} defined inductively by:*

D0(G)=G;Dn+1(G)=D(Dn(G))for n∈N. D^0(G) = G; \quad D^{n+1}(G) = D(D^n(G)) \quad \text{for } n \in \mathbf{N}.

Then D0(G)=C1(G)=G, D1(G)=C2(G)=D(G)=(G,G)D^0(G) = C^1(G) = G,\ D^1(G) = C^2(G) = D(G) = (G, G). For all n \in \mathbf{N}, D^n(G) \subset C^{2^n}(G), as is seen by induction on n using formula (7) of no. 3.

Let f:G→G′f : G \to G' be a group homomorphism. It is seen, by induction on n, that f(Dn(G))⊂Dn(G′)f(D^n(G)) \subset D^n(G') and that, if ff is surjective, f(Dn(G))=Dn(G′)f(D^n(G)) = D^n(G'). In particular, for all n∈Nn \in \mathbf{N}, Dn(G)D^n(G) is a characteristic (and therefore normal) subgroup of G. For all n∈Nn \in \mathbf{N}, the group Dn(G)/Dn+1(G)D^n(G)/D^{n+1}(G) is a commutative normal (but not in general central) subgroup of G/Dn+1(G)G/D^{n+1}(G).

Let (G0,G1,…)(G_0, G_1, \ldots) be a decreasing sequence of subgroups of G such that: (1) G0=GG_0 = G; (2) for all ii, Gi+1G_{i+1} is normal in GiG_i and Gi/Gi+1G_i/G_{i+1} is commutative. Then Di(G)⊂GiD^i(G) \subset G_i for all ii, as is seen by induction on ii.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed edition, 1998, Springer. Not translated.