Bourbaki

Proposition 3

Tag 05FJ, permanent. Cite it as [Bourbaki, Tag 05FJ].

Algebra, chapter I, § 7. Free monoids, free groups

Let M be a monoid. Every mapping f of X into M extends uniquely to a homomorphism of Mo(X) into M.

Let gg be a homomorphism of Mo(X)\mathrm{Mo}(\mathbf{X}) into MM extending ff. If w=(xi)1≤i≤nw = (x_i)_{1 \leq i \leq n} is a word, then w=∏i=1nxiw = \prod_{i=1}^n x_i in the monoid Mo(X)\mathrm{Mo}(\mathbf{X}), whence

g(w)=∏i=1ng(xi)=∏i=1nf(xi) g(w) = \prod_{i=1}^n g(x_i) = \prod_{i=1}^n f(x_i)

in the monoid MM (§ 1, no. 2, formula (2)). This proves the uniqueness of gg.

Let h(w)=∏i=1nf(xi)h(w) = \prod_{i=1}^n f(x_i) for every word w=(xi)1≤i≤nw = (x_i)_{1 \leq i \leq n}. The associativity theorem (§ 1, no. 3, Theorem 1) and the definition of product in Mo(X)\mathrm{Mo}(\mathbf{X}) imply h(ww′)=h(w)h(w′)h(ww') = h(w)h(w'). By convention the empty product h(e)h(e) is the identity element of MM and h(x)=f(x)h(x) = f(x) for x∈Xx \in \mathbf{X}. Hence hh is a homomorphism of Mo(x)\mathrm{Mo}(x) into MM extending ff.

Let u:X→Yu : \mathbf{X} \to \mathbf{Y} be a mapping. By Proposition 3, there exists one and only one homomorphism of Mo(X) into Mo(Y) which coincides with u on X; it is denoted by Mo(u). It maps a word (xi)1≤i≤n(x_i)_{1 \leq i \leq n} to the word (u(xi))1≤i≤n(u(x_i))_{1 \leq i \leq n}. As in the case of magmas (no. 1), the equation Mo(v \circ u) = Mo(v) \circ Mo(u) is established for every mapping v:Y→Zv : Y \to Z and it can be shown that Mo(u) is injective (resp. surjective, bijective) if u is. For every subset S of X, Mo(S) is identified with the submonoid of Mo(X) generated by S.

Let X be a set and (uα,vα)α∈I(u_\alpha, v_\alpha)_{\alpha \in I} be a family of ordered pairs of elements of Mo(X). Let R be the equivalence relation on Mo(X) compatible with the law on Mo(X) and generated by the (uα,vα)(u_\alpha, v_\alpha) (§ 1, no. 6). The monoid Mo(X)/R is called the monoid defined by X and the relators (uα,vα)α∈I(u_\alpha, v_\alpha)_{\alpha \in I}. Let h be the canonical morphism of Mo(X) onto Mo(X)/R. Then Mo(X) is generated by h(X).

Let N be a monoid and (nx)x∈X(n_x)_{x \in X} a family of elements of N. Let k be the morphism of Mo(X) into N such that k(x)=nxk(x) = n_x for all x∈Xx \in X (Proposition 3). If k(uα)=k(vα)k(u_\alpha) = k(v_\alpha) for all α∈I\alpha \in I, there exists one and only one magma morphism f:Mo(X)/R→Nf : Mo(X)/R \to N such that f(h(x))=nxf(h(x)) = n_x for all x∈Xx \in X (§ 1, no. 6, Proposition 9); as k is unital, f is a monoid morphism.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed edition, 1998, Springer. Not translated.