Bourbaki

Proposition 6

Tag 05QM, permanent. Cite it as [Bourbaki, Tag 05QM].

Algebra, chapter II, § 5. Extension of the ring of scalars

Let E be a left A-module and F a right B-module. There exists one and only one Z\mathbf{Z}-homomorphism

ρ∗(F)⊗AE→F⊗Bρ∗(E) \rho_*(F) \otimes_A E \to F \otimes_B \rho^*(E)

mapping y⊗xy \otimes x to y⊗(1⊗x)y \otimes (1 \otimes x) for all x∈Ex \in E and all y∈Fy \in F and this homomorphism is bijective.

By definition the right hand side of (14) is F⊗B(B⊗AE)F \otimes_B (B \otimes_A E), where B is considered as a (B, A)-bimodule, and there is a canonical Z\mathbf{Z}-isomorphism (F⊗BB)⊗AE→F⊗B(B⊗AE)(F \otimes_B B) \otimes_A E \to F \otimes_B (B \otimes_A E) defined in § 3, no. 8, Proposition 8; on the other hand, the canonical isomorphism F→F⊗BBF \to F \otimes_B B of § 3, no. 4, Proposition 4 is an isomorphism for the right A-module structures on the two sides, defined by ρ\rho. Whence the desired isomorphism.

When A and B are commutative, the isomorphism (14) is an A-module isomorphism

ρ∗(F)⊗AE→ρ∗(F⊗Bρ∗(E)). \rho_*(F) \otimes_A E \to \rho_*(F \otimes_B \rho^*(E)).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

Transcribed from the printed edition, 1998, Springer. Not translated.