Bourbaki

Corollary

Tag 05SZ, permanent. Cite it as [Bourbaki, Tag 05SZ].

Algebra, chapter II, § 7. Vector spaces

Let K be a field, E a right vector space over K, F a left vector space over K, (Mα)α∈A(M_\alpha)_{\alpha \in A} a family of vector subspaces of E and (Nβ)β∈B(N_\beta)_{\beta \in B} a family of vector subspaces of F. Then

(⋂α∈AMα)⊗K(⋂β∈BNβ)=⋂(α,β)∈A×B(Mα⊗KNβ). \left( \bigcap_{\alpha \in A} M_\alpha \right) \otimes_K \left( \bigcap_{\beta \in B} N_\beta \right) = \bigcap_{(\alpha, \beta) \in A \times B} (M_\alpha \otimes_K N_\beta).

It is obviously sufficient to prove the particular case

(⋂α∈AMα)⊗KF=⋂α∈A(Mα⊗KF). \left( \bigcap_{\alpha \in A} M_\alpha \right) \otimes_K F = \bigcap_{\alpha \in A} (M_\alpha \otimes_K F).

Clearly the left hand side of (25) is contained in the right hand side. To prove the converse, we consider a basis (fλ)λ∈L(f_\lambda)_{\lambda \in L} of F. Every element of E⊗KFE \otimes_K F can then be expressed uniquely in the form ∑λ∈Lxλ⊗fλ\sum_{\lambda \in L} x_\lambda \otimes f_\lambda, where xλ∈Ex_\lambda \in E (§ 3, no. 7, Corollary 1 to Proposition 7); if E′E' is a vector subspace of E, the relation ∑λ∈Lxλ⊗fλ∈E′⊗KF\sum_{\lambda \in L} x_\lambda \otimes f_\lambda \in E' \otimes_K F is equivalent, by Proposition 14, to xλ∈E′x_\lambda \in E' for all λ∈L\lambda \in L. To say that ∑λ∈Lxλ⊗fλ\sum_{\lambda \in L} x_\lambda \otimes f_\lambda belongs to each of the Mα⊗KFM_\alpha \otimes_K F thus means that for all λ∈L\lambda \in L and all α∈A\alpha \in A, xλ∈Mαx_\lambda \in M_\alpha, that is xλ∈⋂α∈AMαx_\lambda \in \bigcap_{\alpha \in A} M_\alpha for all λ∈L\lambda \in L, which proves that the right hand side of (25) is contained in the left hand side.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed edition, 1998, Springer. Not translated.