Let (xi)i∈I be a family of points in an affine space E and (λi)i∈L a family of elements of K of finite support such that ∑i∈Iλi=1 (resp. ∑i∈Iλi=0*). If a is any point of E, the point x∈E defined by
x−a=i∈I∑λi(xi−a) (resp. the free vector ∑i∈Iλi(xi−a))
is independent of the point considered.
If a′ is another point of E, then
i∑λi(xi−a′)=i∑λi((xi−a)+(a−a′))=i∑λi(x−a)+(i∑λi)(a−a′). If
∑iλi=1, then
∑iλi(xi−a)=(x−a)+(a−a′)=x−a′; if
∑iλi=0, then
∑iλi(x−a′)=∑iλi(x−a); whence the proposition.
Under the conditions of Proposition 1, the point x defined by
x−a=i∈I∑λi(xi−a) (resp. the free vector ∑i∈Iλi(xi−a))
is denoted by ∑i∈Iλixi.
Thus in particular the notation b−a introduced in no. 1 is recovered. When ∑iλi=1, the point x=∑iλixi is called the barycentre of the points xi given the masses λi.
Given m points a1,…,am of E, whose number m is not a multiple of the characteristic of K (V, § 1), the point g=∑i=1mm1ai is called (by an abuse of
language) the barycentre of the points ai (1≤i≤m) (for m=2, we say "midpoint" instead of "barycentre"); it is characterized by the relation
i=1∑m(ai−g)=0.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
Nothing.