Let A be a commutative K-algebra, Mi (1≤i≤n) and P A-modules and H the A-module of A-multilinear mappings of M1×M2×⋯×Mn into P. Suppose that there is given a K-derivation d0:A→A of the algebra A, for each i, a K-linear mapping di:Mi→Mi and a K-linear mapping D:P→P, so that, for 1≤i≤n, (d0,di,di) is a K-derivation of (A,Mi,Mi) into itself and (d0,D,D) is a K-derivation of (A,P,P) into itself. Then there exists a K-linear mapping D′:H→H such that (d0,D′,D′) is a K-derivation of (A,H,H) into itself and
(37) D(f(x1,…,xn))
=(D′f)(x1,…,xn)+i=1∑nf(x1,…,xi−1,dixi,xi+1,…,xn)
for all xi∈Mi for 1≤i≤n and f∈H.
We show that for f∈H, the mapping D′f of M1×M2×⋯×Mn into P defined by (37) is A-multilinear. For a∈A,
(D′f)(ax1,x2,…,xn)=D(af(x1,…,xn))−f(d1(ax1),x2,…,xn)
−ai=2∑nf(x1,…,xi−1,dixi,xi+1,…,xn)
and by hypothesis
D(af(x1,…,xn))=(d0a)f(x1,…,xn)+aD(f(x1,…,xn))
and d1(ax1)=(d0a)x1+a.d1x1, which gives
(D′f)(ax1,x2,…,xn)=a.(D′f)(x1,…,xn)
and linearity in each of the xi is proved similarly. On the other hand,
(D′(af))(x1,…,xn)=D(af(x1,…,xn))
−i=1∑naf(x1,…,xi−1,dixi,xi+1,…,xn)
=(d0a)f(x1,…,xn))+aD(f(x1,…,xn))
−i=1∑naf(x1,…,xi−1,dixi,xi+1,…,xn)
=(d0a)f(x1,…,xn)+a(D′f)(x1,…,xn)
in other words
D′(af)=(d0a)f+a(D′f)
which establishes the proposition.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
Nothing.