Corollary 1
Tag 06FC, permanent. Cite it as [Bourbaki, Tag 06FC].
Algebra, chapter IV, § 6. Symmetric functions
— (i) Let λ,α1,…,αp be elements of A and suppose that f(X)=λ(X−α1)…(X−αp). We have
resp,q(f,g)=λqg(α1)…g(αp). (ii) Let
μ,β1,…,βq be elements of A and suppose further that
g(X)=μ(X−β1)…(X−βq). Then we have
resp,q(f,g)=λqμp1≤i≤p1≤j≤q∏(αi−βj). Assertion (i) follows directly from the formulae (28), (32) and (36). Now Assertion (ii) follows from (i).
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
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