Bourbaki

Lemma 2

Tag 06V3, permanent. Cite it as [Bourbaki, Tag 06V3].

Algebra, V, p. 133, § 16. Differential criteria of separability

Let f:U→Vf : U \to V and g:V→Wg : V \to W be two L-linear mappings. Iff and g each have an index, the same is true of g∘fg \circ f and we have

χ(g∘f)=χ(f)+χ(g). \chi(g \circ f) = \chi(f) + \chi(g).

Put h=g∘fh = g \circ f, and denote by N, N', N'' the kernels off, g, h respectively and by C, C', C'' their cokernels. We have N⊂N′′⊂UN \subset N'' \subset U and f(N′′)=f(U)∩N′f(N'') = f(U) \cap N'; hence there exists a linear mapping fˉ:N′′→N′\bar{f} : N'' \to N' agreeing with f on N'' and with kernel N. The canonical mapping π\pi of V onto C=V/f(U)C = V / f(U) induces a mapping π′\pi' of N' into C whose kernel is f(U)∩N′=fˉ(N′′)f(U) \cap N' = \bar{f}(N''). By passage to quotients g defines a mapping gˉ\bar{g} of C=V/f(U)C = V/f(U) into C′′=W/g(f(U))C'' = W/g(f(U)) whose kernel is clearly (N′+f(U))/f(U)=π′(N′)(N' + f(U))/f(U) = \pi'(N'). Finally the canonical mapping ρ\rho of C′′=W/g(f(U))C'' = W/g(f(U)) onto C′=W/g(V)C' = W/g(V) has the kernel g(V)/g(f(U))=gˉ(C)g(V)/g(f(U)) = \bar{g}(C). To sum up, we have established the exactness of the sequence

0→N→iN′′→fˉN′→π′C→gˉC′′→ρC′→0 0 \to N \xrightarrow{i} N'' \xrightarrow{\bar{f}} N' \xrightarrow{\pi'} C \xrightarrow{\bar{g}} C'' \xrightarrow{\rho} C' \to 0

(where i is the canonical injection of N in N").

!Diagram showing the relationships between N, N', N'', U, V, W, C, C', C'', with arrows indicating mappings and kernels

Fig. 1

By hypothesis N, N', C and C' are of finite dimension; hence the same is true of N'' and C. By Cor. 2 (II, p. 295) we then have

[N:L]−[N′′:L]+[N′:L]−[C:L]+[C′′:L]−[C′:L]=0 [N : L] - [N'' : L] + [N' : L] - [C : L] + [C'' : L] - [C' : L] = 0

whence χ(h)=χ(f)+χ(g)\chi(h) = \chi(f) + \chi(g).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed edition, 2003, Springer. Not translated.