Bourbaki

Example

Tag 0784, permanent. Cite it as [Bourbaki, Tag 0784].

Topological Vector Spaces, chapter I, § 1. Topological vector spaces

If K is a non-discrete valued division ring then the space B(I;K)\mathscr{B}(I ; K) (I, p. 4, Example) is complete (GT, X, § 3.1, cor. 1). This is also true for the space ℓK1(I)\ell_K^1(I) (I, p. 4, Example) with the norm ∥x∥1=∑i∈I∣ξi∣\|x\|_1 = \sum_{i \in I} |\xi_i|: for, if xnx_n is a Cauchy sequence in this space and xn=(ξmi)i∈Ix_n = (\xi_{m_i})_{i \in I}, then for all i∈Ii \in I

∣ξmi−ξni∣≤∥xm−xn∥1; |\xi_{m_i} - \xi_{n_i}| \leq \|x_m - x_n\|_1;

thus, for each i∈Ii \in I, the sequence (ξmi)n≥1(\xi_{m_i})_{n \geq 1} converges to a limit ξi\xi_i in K. Further, for each finite subset J of I

∑i∈J∣ξmi−ξni∣≤∥xm−xn∥1; \sum_{i \in J} |\xi_{m_i} - \xi_{n_i}| \leq \|x_m - x_n\|_1;

and it follows immediately that there exists a constant a>0a > 0, independent of J, m, n such that ∑i∈J∣ξmi−ξni∣≤a\sum_{i \in J} |\xi_{m_i} - \xi_{n_i}| \leq a. Letting m tend to +∞+ \infty, we deduce ∑i∈J∣ξi−ξmi∣≤ε\sum_{i \in J} |\xi_i - \xi_{m_i}| \leq \varepsilon from which ∑i∈I∣ξi∣≤a+∥xn∥1\sum_{i \in I} |\xi_i| \leq a + \|x_n\|_1, which shows that z=(ξi)i∈Iz = (\xi_i)_{i \in I} belongs to ℓK1(I)\ell_K^1(I); further, for all ε>0\varepsilon > 0, there exists n0n_0 such that for n≥n0n \geq n_0 and for every finite set J of I, we have ∑i∈J∣ξi−ξmi∣≤ε\sum_{i \in J} |\xi_i - \xi_{m_i}| \leq \varepsilon; passing to the limit with respect to the directed set of finite subsets of I, we see that ∥z−xn∥1≤ε\|z - x_n\|_1 \leq \varepsilon for n≥n0n \geq n_0, which shows that zz is the limit of the sequence (xn)(x_n) in the normed space ℓK1(I)\ell_K^1(I).

Let KK be a Hausdorff topological division ring, EE a topological vector space on KK and suppose that the completed ring K^\hat{K} is a division ring (this is so when KK is a valued division ring, GT, IX, § 3.3) then the Hausdorff completion E^\hat{E} of EE carries the structure of a complete topological vector space on K^\hat{K} (GT, III, § 6.5); we say that E^\hat{E}, with this structure, is the Hausdorff completion of the topological vector space EE, or simply the completion of EE when EE is Hausdorff.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

  • IX, § 3 not yet on this site
  • X, § 3 not yet on this site
  • III, § 6
Transcribed from the printed volume. Not translated.