Bourbaki

Proposition 1

Tag 07MK, permanent. Cite it as [Bourbaki, Tag 07MK].

Topological Vector Spaces, III, p. 13, § 3. Spaces of continuous linear mappings

Let E be a set, S\mathfrak{S} a family of subsets of E, F a topological vector space and H a vector subspace of FEF^E. In order that the S\mathfrak{S}-topology* be compatible with the vector space structure of H, it is necessary and sufficient that u(M)u(M) is bounded in F for every u∈Hu \in H and every M∈SM \in \mathfrak{S}. If, moreover, F is locally convex, then the S\mathfrak{S}*-topology* on H is locally convex.*

On account of Remarks 1) and 2) above, we see that a necessary and sufficient condition for the S\mathfrak{S}*-topology* to be compatible with the vector space structure of H is that the sets H∩T(M,V)H \cap T(M, V) are absorbent in H (I, p. 7, prop. 4); but this implies that for every u∈Hu \in H, every subset M∈SM \in \mathfrak{S}, and every balanced neighbourhood V of 0 in F, there exists λ≠0\lambda \neq 0 such that u(M)⊂λVu(M) \subset \lambda V; that is to say (III, p. 2) that u(M)u(M) is bounded in F. Finally, the last assertion of the proposition follows from the fact that if V is convex, so is T(M,V)T(M, V).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

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Transcribed from the printed volume. Not translated.