Bourbaki

Proposition 3

Tag 07MS, permanent. Cite it as [Bourbaki, Tag 07MS].

Topological Vector Spaces, chapter III, § 3. Spaces of continuous linear mappings

— Let E and F be two locally convex spaces, F being assumed Hausdorff, and let S\mathfrak{S} be a family of bounded subsets of E. If the union A of the sets of S\mathfrak{S} is total in E, then the space LS(E;F)\mathscr{L}_\mathfrak{S}(E; F) is Hausdorff.

Let u0u_0 be a non-zero element of L(E;F)\mathscr{L}(E; F); since u0u_0 is continuous and A is total in E, there exists an x0x_0 in A such that u0(x0)≠0u_0(x_0) \neq 0. Since F is Hausdorff, there exists a neighbourhood V of 0 in F such that u0(x0)∉Vu_0(x_0) \notin V. Let M∈SM \in \mathfrak{S} be such that x0∈Mx_0 \in M. Then the set U of all u∈L(E;F)u \in \mathscr{L}(E; F) such that u(M)⊂Vu(M) \subset V is a neighbourhood of 0 in L(E;F)\mathscr{L}(E; F), and we have u0∉Uu_0 \notin U, hence L(E;F)\mathscr{L}(E; F) is Hausdorff.

In particular, the following topologies on L(E;F)\mathscr{L}(E; F) are Hausdorff whenever F is Hausdorff : simple convergence, compact convergence, precompact or compact convex, and bounded convergence.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.