Bourbaki

Proposition 4

Tag 07MT, permanent. Cite it as [Bourbaki, Tag 07MT].

Topological Vector Spaces, III, p. 16, § 3. Spaces of continuous linear mappings

Let E, F be two locally convex spaces, and F be Hausdorff. Let the space FEF^E of all mappings from E into F be assigned the topology of simple convergence. Then

(i) The set of linear mappings from E into F is closed in FEF^E.

(ii) If H is an equicontinuous subset of L(E;F)\mathscr{L}(E; F), the closure H‾\overline{H} of H in FEF^E is contained in L(E;F)\mathscr{L}(E; F) and is equicontinuous.

We know that H‾\overline{H} is equicontinuous (GT, X, § 2, No. 3, prop. 6). It remains to prove the assertion (i). Let x, y be in E and λ,μ\lambda, \mu in K, and let A(x,y,λ,μ)A(x, y, \lambda, \mu) be the set of all u∈FEu \in F^E such that

u(λx+μy)−λu(x)−μu(y)=0. u(\lambda x + \mu y) - \lambda u(x) - \mu u(y) = 0 .

This set is closed in FEF^E since the mapping u↦u(x)u \mapsto u(x) from FEF^E into F is continuous for every x∈Ex \in E and since F is Hausdorff. But the set of linear mappings from E into F is equal to

⋂x,y,λ,μA(x,y,λ,μ). \bigcap_{x,y,\lambda,\mu} A(x, y, \lambda, \mu) .

Thus this set is closed in FEF^E.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

  • X, § 2, No. 3 not yet on this site
Transcribed from the printed volume. Not translated.