Bourbaki

Proposition 9

Tag 07PM, permanent. Cite it as [Bourbaki, Tag 07PM].

Topological Vector Spaces, III, p. 32, § 5. Hypocontinuous bilinear mappings

Let R,S,TR, S, T be three locally convex Hausdorff spaces. Suppose that the spaces L(R;S),L(S;T),L(R;T)\mathscr{L}(R; S), \mathscr{L}(S; T), \mathscr{L}(R; T) are each assigned the topology of simple (resp. compact, bounded) convergence. Then the bilinear mapping (u,v)↦v∘u(u, v) \mapsto v \circ u from L(R;S)×L(S;T)\mathscr{L}(R; S) \times \mathscr{L}(S; T) into L(R;T)\mathscr{L}(R; T) is (S,T)(\mathfrak{S}, \mathfrak{T})-*hypocontinuous*, where T\mathfrak{T} is the family of equicontinuous subsets of L(S;T)\mathscr{L}(S; T), and S\mathfrak{S} the family of finite (resp. compact, bounded) subsets of L(R;S)\mathscr{L}(R; S).

We first prove that (u,v)↦v∘u(u, v) \mapsto v \circ u is T\mathfrak{T}-hypocontinuous. Let H be an equicontinuous set in L(S;T)\mathscr{L}(S; T), let W be a neighbourhood of 0 in T and let M be a finite (resp. compact, bounded) subset of R. We must show that there exists a neighbourhood V of 0 in S such that if u(M)⊂Vu(M) \subset V and v∈Hv \in H, then v(u(M))⊂Wv(u(M)) \subset W. But for this, it is enough to have v(V)⊂Wv(V) \subset W for all v∈Hv \in H, and the existence of such a neighbourhood follows from the equicontinuity of H.

To see that (u,v)↦v∘u(u, v) \mapsto v \circ u is S\mathfrak{S}-hypocontinuous, we shall prove that, for every neighbourhood W of 0 in T, every finite (resp. compact, bounded) subset M of R and every finite (resp. compact, bounded) subset L of L(R;S)\mathscr{L}(R; S) there exists a finite (resp. compact, bounded) subset N of S such that the relations v(N)⊂Wv(N) \subset W and u∈Lu \in L imply that v(u(M))⊂Wv(u(M)) \subset W. Evidently it is enough to show that we can take N=⋃u∈Lu(M)N = \bigcup_{u \in L} u(M), i.e. that the set N is finite (resp. compact, bounded) whenever L and M are. This is immediate if L and M are finite, or if M is bounded in R and L is bounded in L(R;S)\mathscr{L}(R; S) (for the topology of bounded convergence, cf. III, p. 22). Finally, we show that if M is compact in R and L is compact in L(R;S)\mathscr{L}(R; S) for the topology of compact convergence, then N is compact in S. But if uMu_M is the restriction to M of u∈Lu \in L, the mapping u↦uMu \mapsto u_M from L into the space C(M;S)\mathscr{C}(M; S) of all continuous mappings from M into S, with the topology of uniform convergence, is continuous; hence the image of L under this mapping is compact, and our assertion then follows from the continuity of the map (w,x)↦w(x)(w, x) \mapsto w(x) from C(M;S)×M\mathscr{C}(M; S) \times M into S (GT, X, § 1, No. 6, prop. 9).

In the two corollaries that follow, we assume as in prop. 9, that the spaces L(R;S)\mathscr{L}(R; S), L(S;T)\mathscr{L}(S; T), L(R;T)\mathscr{L}(R; T) are all three assigned the topology of simple convergence, or all three the topology of compact convergence, or all three that of bounded convergence.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Transcribed from the printed volume. Not translated.