Bourbaki

Theorem 2

Tag 07ZM, permanent. Cite it as [Bourbaki, Tag 07ZM].

Topological Vector Spaces, V, p. 23, § 2. Orthogonal families in a hilbertian space

For every orthonormal set L in a hilbertian space E, there exists an orthonormal basis B of E containing L.

In fact, let D\mathfrak{D} be the family of all orthonormal subsets of E, linearly ordered by inclusion; it is immediate that this family has finite character (S, III, § 4, No. 5). Hence there exists a maximal family B in D\mathfrak{D} containing L, by th. 1 of S, III, § 4, No. 5. It remains to prove that B is a total set. If not, there will exist a vector y≠0y \neq 0 which is orthogonal to all the vectors of B (V, p. 22, prop. 5), and multiplying y by a suitable scalar, we can assume that ∥y∥=1\|y\| = 1; then, B∪{y}B \cup \{y\} will be an orthonormal set distinct from B and containing B; this contradicts the definition of B; hence the theorem.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

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Cites

Transcribed from the printed volume. Not translated.