Bourbaki

Proposition 7

Tag 081A, permanent. Cite it as [Bourbaki, Tag 081A].

Topological Vector Spaces, chapter V, § 4. Some classes of operators in hilbertian spaces

For u∈L(E)u \in \mathscr{L}(E) to be normal, it is necessary and sufficient that ∥u(x)∥=∥u∗(x)∥\|u(x)\| = \|u^*(x)\| for all x∈Ex \in E.

We define a hermitian form Φ\Phi on EE by

Φ(x,y)=⟨uu∗(x)∣y⟩−⟨u∗u(x)∣y⟩. \Phi(x, y) = \langle uu^*(x)|y \rangle - \langle u^*u(x)|y \rangle .
For uu to be normal, it is necessary and sufficient that Φ=0\Phi = 0. By the polarization formulas (V, p. 2), this is equivalent to Φ(x,x)=0\Phi(x, x) = 0 for all x∈Ex \in E. The proposition now follows since
Φ(x,x)=∥u∗(x)∥2−∥u(x)∥2. \Phi(x, x) = \|u^*(x)\|^2 - \|u(x)\|^2 .

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

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Transcribed from the printed volume. Not translated.