Let E and F be two hilbertian spaces. A continuous linear mapping u from E into F is called a Hilbert-Schmidt mapping if the trace of the positive endomorphism u∗u of E is finite. The set of all Hilbert-Schmidt mappings from E into F is denoted by L2(E,F).
When E=F, we write L2(E) for L2(E;E).
For every u∈L(E,F), let ∥u∥2=Tr(u∗u)1/2, so that u belongs to L2(E;F) if and only if ∥u∥2 is finite. By the definition of the trace, we get
∥u∥22=x1,…,xmsupi=1∑m∥u(xi)∥2
where (x1,…,xm) range over the set of finite orthonormal sequences in E. In particular, taking m=1 in formula (32), we have
∥u∥≤∥u∥2(u∈L(E;F)).
Let (ei)i∈I be an orthonormal basis of E and (fj)j∈J an orthonormal basis of F. By formula (25) of V, p. 50 and the Parseval’s relation (V, p. 22), we have
∥u∥22=i∈I∑∥u(ei)∥2=i,j∑∣⟨fj∣u(ei)⟩∣2.
Since ∣⟨fj∣u(ei)⟩∣=∣⟨ei∣u∗(fj)⟩∣, formula (34) implies that
∥u∗∥2=∥u∥; hence, the adjoint of a Hilbert-Schmidt mapping is a Hilbert-Schmidt mapping. Let
E1,F1 be hilbertian spaces and
v:E1→E,w:F→F1 continuous linear mappings. From (32), we deduce immediately that
∥wu∥2≤∥w∥.∥u∥2. By (35), (36) and the relation
uv=(v∗u∗)∗, we get
∥uv∥2≤∥u∥2∥v∥. In particular, if
u belongs to
L2(E,F) then
wuv belongs to
L2(E1,F1).
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
Nothing.