Bourbaki

Proposition 2

Tag 0833, permanent. Cite it as [Bourbaki, Tag 0833].

Functions of a Real Variable, chapter I, § 1. FIRST DERIVATIVE

Let EE and FF be two topological vector spaces over R\mathbf{R}, and uu a continuous linear map from EE into FF. If ff is a vector function defined on an interval I⊂RI \subset \mathbf{R}, taking values in EE, and differentiable at the point x0∈Ix_0 \in I, then the composite function u∘fu \circ f has a derivative equal to u(f′(x0))u(f'(x_0)) at x0x_0.

Indeed, since u(f(x))−u(f(x0))x−x0=u(f(x)−f(x0)x−x0)\frac{u(f(x)) - u(f(x_0))}{x - x_0} = u \left( \frac{f(x) - f(x_0)}{x - x_0} \right), this follows from the continuity of uu.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

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Transcribed from the printed volume. Not translated.