If E is a topological algebra over R (cf. Introduction), the product xy of two elements of E is a continuous bilinear function of (x,y); if f and g have their values in E and are differentiable at the point x0, then the function x↦f(x)g(x) has a derivative equal to f′(x0)g(x0)+f(x0)g′(x0) at x0. In particular, if U(x)=(αij(x)) and V(x)=(βij(x)) are two square matrices of order n, differentiable at x0, their product UV has a derivative equal to U′(x0)V(x0)+U(x0)V′(x0) at x0 (where U′(x)=(αij′(x)) and V′(x)=(βij′(x))).
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.