Bourbaki

Remark 2

Tag 0854, permanent. Cite it as [Bourbaki, Tag 0854].

Functions of a Real Variable, chapter I, § 3. DERIVATIVES OF HIGHER ORDER

With the same hypotheses, the coefficients aia_i in (11) are determined recursively by the relations

a0=f(a) a_0 = f(a)
a1=lim⁡x→af(x)−f(a)x−a a_1 = \lim_{x \to a} \frac{f(x) - f(a)}{x - a}
a2=lim⁡x→af(x)−f(a)−a1(x−a)(x−a)2 a_2 = \lim_{x \to a} \frac{f(x) - f(a) - a_1(x - a)}{(x - a)^2}
… \ldots
an=lim⁡x→af(x)−f(a)−a1(x−a)−⋯−an−1(x−a)n−1(x−a)n. a_n = \lim_{x \to a} \frac{f(x) - f(a) - a_1(x - a) - \cdots - a_{n-1}(x - a)^{n-1}}{(x - a)^n}.

In the case a=0a = 0 one concludes, in particular, that if f(xp)f(x^p) (pp an integer > 0) has a derivative of order pnpn on a neighbourhood of 0 then the Taylor expansion of order pnpn of this function is simply

f(xp)=a0+a1xp+a2x2p+⋯+anxnp+rn(xp) f(x^p) = a_0 + a_1 x^p + a_2 x^{2p} + \cdots + a_n x^{np} + r_n(x^p)

where rn(xp)r_n(x^p) is the remainder in the expansion (cf. V, p. 222).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

Transcribed from the printed volume. Not translated.