If w is a continuous real function on the interval [t0, t_1] and satisfies the inequality*
w(t)≤φ(t)+∫t0tk(s)w(s)ds (12)
where φ is a regulated function ≥0 on [t0,t1], then, for t0≤t≤t1,
w(t)≤φ(t)+∫t0tφ(s)k(s)exp(∫stk(τ)dτ)ds. (13)
Put y(t)=∫t0tk(s)w(s)ds; the relation (12) implies that
y′(t)−k(t)y(t)≤φ(t)k(t) (14)
on the complement of a countable set.
Put z(t)=y(t)exp(−∫t0tk(s)ds); then (14) is equivalent to
z′(t)≤φ(t)k(t)exp(−∫t0tk(s)ds).
On applying the mean value theorem (I, p. 15, th. 2) to this inequality, and noting that z(t0)=0, we obtain
z(t)≤∫t0tφ(s)k(s)exp(−∫t0sk(τ)dτ)ds
whence
y(t)≤∫t0tφ(s)k(s)exp(∫stk(τ)dτ)ds
and since w(t)≤φ(t)+y(t) one thus obtains (13).
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
Nothing.