Bourbaki

Theorem 2

Tag 08S9, permanent. Cite it as [Bourbaki, Tag 08S9].

Integration, chapter IV, § 4. Integrable functions and sets

— Let AA be a set of indices, filtered by a filter F\mathfrak{F} with a countable base. Let (fα)α∈A(f_\alpha)_{\alpha \in A} be a family of integrable functions that, with respect to the filter F\mathfrak{F}, converge pointwise almost everywhere to a function ff; if there exists a numerical function g⩾0g \geqslant 0 such that ∫∗g d∣μ∣<+∞\int^* g \, d|\mu| < +\infty and such that ∣fα(x)∣⩽g(x)|f_\alpha(x)| \leqslant g(x) almost everywhere in XX for each α∈A\alpha \in A, then the function ff is integrable and

∫f dμ=lim⁡F∫fα dμ. \int f \, d\mu = \lim_{\mathfrak{F}} \int f_\alpha \, d\mu .

The theorem follows from Lebesgue’s theorem (§ 3, No. 7, Cor. of Th. 6) since, under the conditions of the statement, fαf_\alpha converges in mean to ff with respect to F\mathfrak{F}.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.