Bourbaki

Proposition 10

Tag 08VE, permanent. Cite it as [Bourbaki, Tag 08VE].

Integration, chapter IV, § 5. Measurable functions and sets

— Let F be a separable Banach space, F' its dual, and (an′)(\mathbf{a}'_n) a weakly dense sequence in the unit ball of F' (TVS, III, § 3, No. 4, Cor. 2 of Prop. 6).¹ For a mapping f of X into F to be measurable, it is necessary and sufficient that for every n the scalar function x↦⟨f(x),an′⟩x \mapsto \langle \mathbf{f}(x), \mathbf{a}'_n \rangle be measurable.

The condition being obviously necessary (No. 3, Th. 1), let us prove that it is sufficient; it suffices to verify condition a) of Th. 4 and, to this end,

¹ See the footnote at the end of § 2, No. 4.

it will suffice by the principle of localization to prove that, for every compact subset K of X and every closed ball B⊂FB \subset F, with center aa and radius rr, the set A=K∩f−1(B)A = K \cap f^{-1}(B) is measurable; now, for every z∈Fz \in F,

∣z∣=sup⁡n∣⟨z,an′⟩∣/∣an′∣; |z| = \sup_n |\langle z, a'_n \rangle| / |a'_n|;

AA is thus the intersection of KK and the sets defined by

∣⟨f(x),an′⟩−⟨a,an′⟩∣≤r∣an′∣; |\langle f(x), a'_n \rangle - \langle a, a'_n \rangle| \leq r |a'_n|;

as these sets are measurable by hypothesis, AA is measurable.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Cites

Transcribed from the printed volume. Not translated.