Bourbaki

Example 1

Tag 090W, permanent. Cite it as [Bourbaki, Tag 090W].

Integration, chapter V, § 3. Integration of positive measures

Suppose that T is a discrete space, and that μ is the measure on T defined by placing a mass +1 at each point of T (Ch. III, §1, No. 3). Let h be a function ⩾0\geqslant 0 defined on T; since the function h is lower semi-continuous (even continuous) on T, μ∗(h)=μ∙(h)=∑t∈Th(t)\mu^*(h) = \mu^\bullet(h) = \sum_{t \in T} h(t) (Ch. IV, §1, No. 1, Example).

For the measure μ, the notions of integrable function and essentially integrable function are therefore identical. This being so, to say that a mapping t↦λtt \mapsto \lambda_t of T into M+(X)\mathscr{M}_+(X) is scalarly essentially μ-integrable amounts to saying that the family (λt)t∈T(\lambda_t)_{t \in T} is summable (§2, No. 1), and one then has ∫λt dμ(t)=∑t∈Tλt\int \lambda_t\, d\mu(t) = \sum_{t \in T} \lambda_t. Note that the mapping t↦λtt \mapsto \lambda_t is vaguely continuous.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Cites

Transcribed from the printed volume. Not translated.