Let F, F′ and G be three Banach spaces, and let (x,y)↦[x⋅y] be a continuous bilinear mapping of F×F′ into G. Let f (resp. f′) be a function defined on T (resp. T′) with values in F (resp. F′) and essentially integrable for μ (resp. μ′). Let g be the function (t,t′)↦[f(t)⋅f′(t′)]; then g is essentially integrable for μ⊗μ′, and
∬[f(t)⋅f′(t′)]dμ(t)dμ′(t′)=[(∫fdμ(t))⋅(∫f′(t′)dμ′(t′))].
If, moreover, f and f′ are integrable, then g is integrable.
The function (t,t′)↦[f(t)⋅f′(t′)] is (μ⊗μ′)-measurable by Cor. 1 of Prop. 3. On the other hand, if b denotes the norm of the bilinear mapping (x,y)↦[x⋅y], then
∬∙∣[f(t)⋅f′(t′)]∣dμ(t)dμ′(t′)≤b∬∙∣f(t)∣⋅∣f′(t′)∣dμ(t)dμ′(t′)
=b(∫∙∣f(t)∣dμ(t))(∫∙∣f′(t′)∣dμ′(t′))
by virtue of Prop. 8. This shows that [f(t)⋅f′(t′)] is essentially integrable for μ⊗μ′ (§ 1, No. 3, Prop. 9). Suppose that f and f′ are integrable: then f and f′ are moderated, and g is moderated (Cor. 2 of Prop. 5) therefore integrable (§ 1, No. 3, Cor. of Prop. 9). In this case the formula (14) follows from the Lebesgue–Fubini theorem and the linearity of the integral (Ch. IV, § 4, No. 2, Th. 1). To complete the treatment of the case that f and f′ are essentially integrable, one then applies (14) to two integrable functions f1 and f1′, equal locally almost everywhere to f and f′, on observing that [f⋅f′]=[f1⋅f1′] locally almost everywhere in T×T′ (Prop. 4).
This result extends to the product of complex measures.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
Nothing.