The linear representations γχ of G in C(X) and K(X) are continuous.
The mapping (s,f)↦(s,γ(s)f) of G×C(X) into G×C(X) is continuous (No. 2, Lemma 3). On the other hand, the mapping (s,f)↦χ(s,⋅)f of G×C(X) into C(X) is continuous; for, if s tends to s0 in G, then χ(s,⋅) tends to χ(s0,⋅) uniformly on every compact subset of X; if, moreover, f tends to f0 in C(X), then χ(s,⋅)f tends to χ(s0,⋅)f0 uniformly on every compact subset of X, whence our assertion. Thus the representation γχ of G in C(X) is continuous.
Let us show that the representation γχ of G in K(X) is continuous. Since K(X) is the direct limit of Banach spaces, it is barreled (TVS, III, §4, No. 1, Cor. 3 of Prop. 3), thus it suffices to prove that γχ is separately continuous (No. 1, Prop. 1). Now, let H be a compact subset of X and let s0∈G. Let V be a compact neighborhood of s0 in G, and let L = VH, which is compact in X. For every f∈K(X,H), the support of γχ(s0)f is contained in L, and
x∈Xsup∣(γχ(s0)f)(x)∣≤x∈Lsup∣χ(s0−1,x)∣⋅x∈Xsup∣f(x)∣, therefore
f↦γχ(s0)f is a continuous linear mapping of
K(X,H) into
K(X,L); it follows that
f↦γχ(s0)f is a continuous linear mapping of
K(X) into itself (TVS, II, §4, No. 4, Prop. 5). On the other hand, the topology of
K(X,L) is induced by that of
C(X). By what has already been proved, the mapping
s↦γχ(s)f of V into
K(X,L) is continuous. This completes the proof that
γχ is separately continuous.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
Nothing.