Bourbaki

Corollary 4

Tag 09VC, permanent. Cite it as [Bourbaki, Tag 09VC].

Lie Groups and Lie Algebras, chapter I, § 2. Enveloping algebra of a Lie algebra

Let S′n⊂Tn{S'}^n \subset T^n be the set of homogeneous symmetric tensors of order n. Suppose that K is a field of characteristic 0. Then the composite mapping of the canonical mappings

Sn→S′n→Un S^n \to {S'}^n \to U_n

is an isomorphism of the vector space SnS^n onto a supplement of Un−1U_{n-1} in UnU_n.

This follows from Corollary 1 taking W=S′nW = {S'}^n.

Suppose henceforth that K is a field of characteristic 0. Let ηn\eta_n be the mapping of SnS^n into UnU_n just defined. Let Un=ηn(Sn)U^n = \eta_n(S^n). The vector space UU is the direct sum of the UnU^n. The ηn\eta_n define an isomorphism η\eta of the vector space S=∑nSnS = \sum_n S^n onto the vector space U=∑nUnU = \sum_n U^n, called the canonical isomorphism of S onto U; this is not an algebra isomorphism. We have the commutative diagram:

Un↗ψn↑ηn↘θnS′nGn↘τn↗ωnSn \begin{array}{ccccc} & & U^n & & \\ & \nearrow \psi_n & \uparrow \eta_n & \searrow \theta_n & \\ {S'}^n & & & & G^n \\ & \searrow \tau_n & & \nearrow \omega_n & \\ & & S^n & & \end{array}

where each arrow represents a vector space isomorphism. If x1,x2,…,xnx_1, x_2, \ldots, x_n are in gg, ηn\eta_n maps the product x1x2…xnx_1 x_2 \ldots x_n, calculated in SS, to the element

1n!∑σ∈Snxσ(1)xσ(2)⋯xσ(n) \frac{1}{n!} \sum_{\sigma \in S_n} x_{\sigma(1)} x_{\sigma(2)} \cdots x_{\sigma(n)}

calculated in UU.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.