Bourbaki

Proposition 1

Tag 09Y2, permanent. Cite it as [Bourbaki, Tag 09Y2].

Lie Groups and Lie Algebras, chapter I, § 5. Solvable Lie algebras

Subalgebras and quotient algebras of a solvable Lie algebra are solvable. Every extension of a solvable algebra by a solvable algebra is solvable. Every finite product of solvable algebras is solvable.

Let gg be a Lie algebra, g′g' a subalgebra, hh an ideal of gg, t=g/ht = g/h and ϕ\phi the canonical mapping of gg onto tt. If gg is solvable then Dkg={0}D^k g = \{0\} for some integer kk, hence Dkg′⊂Dkg={0}D^k g' \subset D^k g = \{0\}, Dkt=ϕ(Dkg)={0}D^k t = \phi(D^k g) = \{0\} and hence g′g' and tt are solvable. If hh and tt are solvable there exist integers s,ts, t such that

Dsh=Dtt={0}; D^s h = D^t t = \{0\};

then Dtg⊂hD^t g \subset h, hence Ds+tg=Ds(Dtg)⊂Dsh={0}D^{s+t} g = D^s(D^t g) \subset D^s h = \{0\} and gg is solvable. The last assertion follows from the second by induction on the number of factors.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.