Bourbaki

Example

Tag 0AHQ, permanent. Cite it as [Bourbaki, Tag 0AHQ].

Lie Groups and Lie Algebras, chapter III, § 7. Lie groups over an ultrametric field

Suppose that K is locally compact. Let U be the set of invertible elements of A; it is a compact open subgroup of the Lie group K∗K^*. Then U⊂(K∗)fU \subset (K^*)_f by Proposition 13; on the other hand, if x∈K∗x \in K^* is such that x∉Ux \notin U, either xnx^n tends to 0 as n tends to +∞+\infty, or xnx^n tends to 0 as n tends to −∞-\infty; hence U=(K∗)fU = (K^*)_f. The function log⁡K∗\log_{K^*} is defined and analytic on U, with values in L(K∗)=KL(K^*) = K, and such that log⁡K∗(xy)=log⁡K∗(x)+log⁡K∗(y)\log_{K^*}(xy) = \log_{K^*}(x) + \log_{K^*}(y) for all x,yx, y in U; the elements x of U such that log⁡K∗(x)=0\log_{K^*}(x) = 0 are the roots of unity of K.

We again use the notation of nos. 3, 4 and 5.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Transcribed from the printed volume. Not translated.