Bourbaki

Proposition 5

Tag 0ANT, permanent. Cite it as [Bourbaki, Tag 0ANT].

Lie Groups and Lie Algebras, chapter IV, § 2. Tits Systems

Let P1P_1 and P2P_2 be two parabolic subgroups of GG. Then P1∩P2P_1 \cap P_2 contains a conjugate of TT.

By first transforming P1P_1 and P2P_2 by an inner automorphism of GG, we may assume that B⊂P1B \subset P_1. Let g∈Gg \in G be such that gB2g−1⊂P2gB_2g^{-1} \subset P_2. By Th. 1, there exist n∈Nn \in N and b,b′∈Bb, b' \in B such that g=bnb′g = bn b'. Since TT is normal in NN,

P2⊃gB2g−1=bnBn−1b−1⊃bnTn−1b−1=bTb−1 P_2 \supset gB_2g^{-1} = bnBn^{-1}b^{-1} \supset bnTn^{-1}b^{-1} = bTb^{-1}

and

P1⊃B⊃bTb−1, P_1 \supset B \supset bTb^{-1},

which proves the proposition.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Transcribed from the printed volume. Not translated.