Let P1 and P2 be two parabolic subgroups of G. Then P1∩P2 contains a conjugate of T.
By first transforming P1 and P2 by an inner automorphism of G, we may assume that B⊂P1. Let g∈G be such that gB2g−1⊂P2. By Th. 1, there exist n∈N and b,b′∈B such that g=bnb′. Since T is normal in N,
P2⊃gB2g−1=bnBn−1b−1⊃bnTn−1b−1=bTb−1
and
P1⊃B⊃bTb−1,
which proves the proposition.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.