Bourbaki

Corollary

Tag 0ATP, permanent. Cite it as [Bourbaki, Tag 0ATP].

Lie Groups and Lie Algebras, chapter V, § 6. The Coxeter transformation

Let R0R_0 be the set of unit vectors of VV orthogonal to an element of H\mathfrak{H}. If WW is irreducible,

∑u∈R0(x∣u)2=h(x∣x) \sum_{u \in R_0} (x|u)^2 = h(x|x)

for all x∈Vx \in V.

Put f(x)=∑u∈R0(x∣u)2f(x) = \sum_{u \in R_0} (x|u)^2. It is clear that ff is a positive quadratic form invariant under WW, and non-degenerate since the eie_i form a basis of VV. Since

W is irreducible, there exists a constant β\beta such that f(x)=β(x∣x)f(x) = \beta(x|x) (§ 2, no. 1, Prop. 1). If (xi)1≤i≤l(x_i)_{1 \leq i \leq l} is an orthonormal basis of V for the scalar product (x∣y)(x|y), then

βl=∑i=1lβ(xi∣xi)=∑i=1lf(xi)=∑i=1l∑u∈R0(xi∣u)2=∑u∈R01=Card(R0)=2Card(H)=hl. \beta l = \sum_{i=1}^l \beta(x_i|x_i) = \sum_{i=1}^l f(x_i) = \sum_{i=1}^l \sum_{u \in R_0} (x_i|u)^2 \\ = \sum_{u \in R_0} 1 = \mathrm{Card}(R_0) = 2\mathrm{Card}(\mathfrak{H}) = hl.
Thus β=h\beta = h, which proves (4).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.