Bourbaki

Remark 2

Tag 0B2L, permanent. Cite it as [Bourbaki, Tag 0B2L].

General Topology, chapter I, § 4. Product of topological spaces

It is possible for all the partial mappings determined by a map f:X1×X2→Yf : X_1 \times X_2 \to Y to be continuous without ff being continuous on X1×X2X_1 \times X_2 (cf. Chapter IX, § 5, Exercise 23). \* For example if ff is the mapping of the real plane R2\mathbf{R}^2 into R\mathbf{R} defined by

f(x,y)=xy/(x2+y2)if(x,y)≠(0,0) f(x, y) = xy/(x^2 + y^2) \quad \text{if} \quad (x, y) \neq (0, 0)
and f(0,0)=0f(0, 0) = 0, then all the partial mappings are continuous; but ff is not continuous at (0,0)(0, 0), since f(x,x)=1/2f(x, x) = 1/2 if x≠0x \neq 0.

If gg is a mapping of X1X_1 into YY, continuous at a point a1a_1, then the mapping (x1,x2)→g(x1)(x_1, x_2) \to g(x_1) of X1×X1→YX_1 \times X_1 \to Y is continuous at all points (a1,x2)(a_1, x_2), for it is the composition of gg and the projection onto X1X_1.

The results of this subsection are easily extended to an arbitrary product ∏i∈IXi\prod_{i \in I} X_i of topological spaces by remarking that this product is homeomorphic to the product (∏i∈JXi)×(∏i∈KXi)\left( \prod_{i \in J} X_i \right) \times \left( \prod_{i \in K} X_i \right) for any partition (J,K)(J, K) of II (no. 1, Proposition 2).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.