Let I be a directed set and J a cofinal subset of I. Let (Xα,fαβ) be an inverse system of topological spaces indexed by I; let X=limXα and let fα:X→Xα be the canonical mapping. Then the family of sets fα−1(Uα), where α runs through J and Uα runs through a base Bα of the topology of Xα for each α∈J, is a base of the topology of X.
From § 2, no. 3 we know that the finite intersections of sets of the form fα−1(Uα) (α∈I,Uα open in Xα) form a base of the topology of X. If (αi)1≤i≤n is a finite family of indices of I, then there exists γ∈J such that αi≤γ for 1≤i≤n; hence fαi=fαiγ∘fγ; if we put
Vγ=i⋂fαiγ−1(Uαi),
then we have
fγ−1(Vγ)=i⋂fαi−1(Uαi);
but Vγ is open and is therefore a union of sets belonging to Bγ. Hence the result.
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.