Bourbaki

Remark 2

Tag 0BMD, permanent. Cite it as [Bourbaki, Tag 0BMD].

General Topology, chapter III, § 5. Infinite sums in commutative groups

The definition of a summable family does not involve any ordering of the index set II, and we may therefore say that the notion of a sum thus defined is commutative. More precisely, we have the following property: let (xi)i∈I(x_i)_{i \in I} be a summable family and let φ\varphi be a bijective mapping of an index set KK onto the set II; then if we put yx=xφ(x)y_x = x_{\varphi(x)}, the family (yx)x∈K(y_x)_{x \in K} is summable and has the same sum as (xi)(x_i). For if s=∑i∈Ixis = \sum_{i \in I} x_i, and if ∑i∈Jxi∈s+V\sum_{i \in J} x_i \in s + V for every finite subset JJ containing the finite subset J0J_0, then we shall have ∑x∈Lyx∈s+V\sum_{x \in L} y_x \in s + V for every finite subset LL of KK containing φ‾(J0)\overline{\varphi}(J_0).

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.