Bourbaki

Proposition 4

Tag 0BN9, permanent. Cite it as [Bourbaki, Tag 0BN9].

General Topology, chapter III, § 6. Topological groups with operators; topological rings division rings and fields

Let E, F be two commutative topological groups with operators, and let u be a continuous linear mapping of E into F. In order that there should exist a continuous linear mapping v of F into E such that v∘uv \circ u is the identity mapping of E onto itself (in which case u is said to be left invertible and v is said to be a left inverse of u) it is necessary and sufficient that u is a (topological) isomorphism of E onto u(E), and that u(E) has a topological complement in F.

The conditions are sufficient, for if they are satisfied we obtain a left inverse v of u by taking the composition of the isomorphism of u(E) onto E which is the inverse of u, with a continuous projector of F onto u(E).

The conditions are necessary. For the relation v(u(x))=xv(u(x)) = x shows that u‾1(o)={o}\overline{u}^1(o) = \{ o \}; u is therefore a bijection of E onto u(E), and since the restriction of v to u(E) is continuous, it follows that u is an isomorphism of E onto u(E). On the other hand, if we put q=u∘vq = u \circ v, then q is a continuous linear mapping of F onto u(E) such that q2=qq^2 = q, which proves (Corollary to Proposition 2) that u(E) has a topological complement in F.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Transcribed from the printed volume. Not translated.