Bourbaki

Proposition 6

Tag 0BNG, permanent. Cite it as [Bourbaki, Tag 0BNG].

General Topology, chapter III, § 6. Topological groups with operators; topological rings division rings and fields

A Hausdorff topological ring AA is isomorphic to a dense subring of a complete Hausdorff ring A^\hat{A}, which is determined up to isomorphism (and is called the completion of AA).

If AA is commutative (resp. has an identity element) then the same is true of A^\hat{A} (principle of extension of identities).

Let AA be a topological ring, not necessarily Hausdorff; let NN be the closure of {0}\{0\} in AA, and let A′=A/NA' = A/N be the Hausdorff ring associated with AA. Then A^′\hat{A}', the completion of A′A', is called the Hausdorff completion of AA and is also denoted by A^\hat{A}. One shows as in § 3, no. 4, Proposition 8 that every continuous ring homomorphism uu of AA with a complete Hausdorff topological ring CC can be uniquely factorized as u=v∘φu = v \circ \varphi, where vv is a continuous homomorphism of A^\hat{A} into CC and φ\varphi is the canonical mapping of AA into A^\hat{A}. If A,BA, B are two topological rings, and u:A→Bu : A \to B is a continuous homomorphism, there is therefore a unique continuous homomorphism u^:A^→B^\hat{u} : \hat{A} \to \hat{B} such that the diagram

A→uBφ↓ψ↓A^→u^B^ \begin{array}{ccc} A & \xrightarrow{u} & B \\ \varphi \downarrow & & \psi \downarrow \\ \hat{A} & \xrightarrow{\hat{u}} & \hat{B} \end{array}

is commutative (φ\varphi and ψ\psi being the canonical mappings); we have only to apply the preceding result to ψ∘u\psi \circ u.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.