Bourbaki

Theorem 1 (Weierstrass)

Tag 0BSF, permanent. Cite it as [Bourbaki, Tag 0BSF].

General Topology, chapter IV, § 6. Continuous and semi-continuous real-valued functions

Let ff be a continuous real-valued function defined on a non-empty quasi-compact space XX. Then there is at least one point a∈Xa \in X such that f(a)=sup⁡x∈X(f(x))f(a) = \sup_{x \in X} (f(x)), and at least one point b∈Xb \in X such that f(b)=inf⁡x∈Xf(x)f(b) = \inf_{x \in X} f(x). For f(X)f(X) is compact (Chapter I, § 9, no. 4, Theorem 2) and therefore closed in R‾\overline{\mathbf{R}}; hence f(X)f(X) contains its bounds.

This theorem is often stated in the form that a continuous real-valued function on a non-empty quasi-compact space attains its bounds.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

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Transcribed from the printed volume. Not translated.