Definition 2
Tag 0BW5, permanent. Cite it as [Bourbaki, Tag 0BW5].
General Topology, chapter VI, § 1. Real number space R^n
Any subset of which is the product of n open (resp. closed) intervals of is called an open (resp. closed) box in . [For it is called an open (resp. closed) rectangle.]
The open boxes in form a base of the topology of (Chapter I, § 4, no. 1); the open boxes which contain a point of form a fundamental system of neighbourhoods of , and so do the closed boxes of for which is an interior point.
Every non-empty open box in is homeomorphic to (Chapter IV, § 4, no. 1, Proposition 1).
It follows that, when , every non-empty open set in has the power of the continuum.
An open (resp. closed) cube of is an open (resp. closed) box which is the product of bounded intervals of equal length [for , it is called an open (resp. closed) square]; the common length of these intervals is called the side (or side-length) of the cube. The open cubes
form a countable fundamental system of neighbourhoods of the point , as runs through the set of all integers or through any sequence of integers increasing to infinity.
Every open (or closed) box in is connected (Chapter I, § 11, no. 4, Proposition 8); in particular, is connected and locally connected.
If is a non-empty open set in , its components are therefore open sets (Chapter I, § 11, no. 6, Proposition 11); and the set of these components is countable, for has a countable dense subset (for example ).
Consider under what conditions a subset of will be relatively compact. By Tychonoff’s theorem (Chapter I, § 9, no. 5, Theorem 3) it is necessary and sufficient that the projections of on the factors of should be relatively compact; by the Borel-Lebesgue theorem (Chapter IV, § 2, no. 2, Theorem 2) this is equivalent to saying that these projections are bounded subsets of . We say that a subset of is bounded if all its projections are bounded subsets of ; thus we have proved:
Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.
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