Bourbaki

Proposition 8

Tag 0BYJ, permanent. Cite it as [Bourbaki, Tag 0BYJ].

General Topology, chapter VII, § 1. Subgroups and quotient groups of $\mathbf{R}^n$

If G1,G2G_1, G_2 are any closed subgroups of Rn\mathbf{R}^n, we have

(G1=G2)∗+G1∗∩G2∗and(G1∩G2)∗=G1∗+G2∗. (G_1 = G_2)^* + G_1^* \cap G_2^* \quad \text{and} \quad (G_1 \cap G_2)^* = G_1^* + G_2^*.

The real number (u∣x+y)(u|x + y) is an integer for all x∈G1x \in G_1 and all y∈G2y \in G_2 if and only if (u∣x)(u|x) is an integer for all x∈G1x \in G_1 and (u∣y)(u|y) is an integer for all y∈G2y \in G_2, because (u∣x+y)=(u∣x)+(u∣y)(u|x + y) = (u|x) + (u|y); hence

(G1+G2)∗=G1∗∩G2∗ (G_1 + G_2)^* = G_1^* \cap G_2^*

for any two subgroups G1,G2G_1, G_2 of Rn\mathbf{R}^n. If now we suppose that G1G_1 and G2G_2 are closed, we have (G1∗+G2∗)∗=G1∩G2(G_1^* + G_2^*)^* = G_1 \cap G_2 by Proposition 6; hence, taking the associated subgroups and applying Proposition 6 again,

(G1∩G2)∗=G1∗+G2∗‾. (G_1 \cap G_2)^* = \overline{G_1^* + G_2^*}.

Bourbaki puts the proof directly after the statement, so what is above is the statement and its proof together.

Cited by

Nothing.

Cites

Transcribed from the printed volume. Not translated.