Bourbaki

习题 11, § 3

标签 07UJ,永久不变。引用为 [Bourbaki, Tag 07UJ]。

拓扑向量空间, IV, p. 60

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令(cmn)(c_{mn})为数>0> 0的双序列,使得cm,n≤cm+1,nc_{m,n} \leq c_{m+1,n},并令E为实数的所有序列x=(xn)x = (x_n)的空间,使得每整数米有pm(x)=∑ncmn∣xn∣<+∞p_m(x) = \sum_n c_{mn} |x_n| < +\infty。 我们赋予 E 由半范数 pmp_m 定义的拓扑,因此拓扑 E 是 Fréchet 空间满足,可数性第一公理; E 的对偶 E′E' 可以用所有序列 x′=(xn′)x' = (x'_n) 的空间来识别,使得 sup⁡ncmn−1∣xn′∣<+∞\sup_n c_{mn}^{-1} |x'_n| < +\infty 至少 1 m,规范的双线性形式 ⟨x,x′⟩\langle x, x' \rangle 可以用 ∑nxnxn′\sum_n x_n x'_n 来识别(IV,p. 47,练习 1, c))。 假设不存在任何子序列(nk)(n_k),其中存在数≥0\geq 0和指标m0m_0的序列(am)(a_m),使得cm,nk≤amcm0,nkc_{m,n_k} \leq a_m c_{m_0,n_k}对于所有m≥m0m \geq m_0和所有k。 Under these conditions, every weakly convergent sequence in E′E' is strongly convergent and consequently (IV, p. 60, exerc. 10) E is a Montel space. (Argue by reductio ad absurdum; if necessary make a transformation of the form (xn)↦(anxn)(x_n) \mapsto (a_n x_n) to reduce to the case where cm0n=1c_{m_0 n} = 1 for all n and some m0m_0, and where there exists a sequence (x(p))p≥0(x^{(p)})_{p \geq 0} which converges weakly to 0 in E', and is such that ∣xn(p)∣≤1|x^{(p)}_n| \leq 1 for every pair (p,n)(p, n), and also that there exists a bounded set B in E, defined by pm(x)≤bmp_m(x) \leq b_m for all m≥0m \geq 0 and such that sup⁡x∈B∣⟨x,x(p)⟩∣≥2δ>0\sup_{x \in B} |\langle x, x^{(p)} \rangle| \geq 2\delta > 0 for every integer p. Under these hypothesis, prove that there exists a strictly increasing sequence (rq)(r_q) of integers, and a sequence (x(q))(x^{(q)}) of points of B such that

∑k=rq+1rq+1∣xk(q)∣>δ \sum_{k=r_q+1}^{r_q+1} |x^{(q)}_k| > \delta

对于每个指标 q。然后通过 reductio ad absurdum 证明,对于每个 q,至少存在一个指标 sqs_q,使得 rq<sq≤rq+1r_q < s_q \leq r_{q+1} 并且对于每整数 m,我们有 cm,sq≤bm2m+2/δc_{m,s_q} \leq b_m 2^{m+2}/\delta,其中与……矛盾假设。)

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