Bourbaki

习题 22, § 2

标签 0C3U,永久不变。引用为 [Bourbaki, Tag 0C3U]。

一般拓扑, IX

Bourbaki marks this one as harder than the rest.

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令XX为具有可数基(Un)(U_n)的豪斯多夫拓扑空间,并令RR为XX上的豪斯多夫等价关系,使得X/RX/R的每个点具有可数基数系统邻域。 证明X/RX/R的拓扑有可数的基。 [Let φ:X→X/R\varphi : X \to X/R be the canonical mapping, and show that the interiors of finite unions of sets φ(Un)\varphi(U_n) form a base of the topology of X/RX/R: if VV is a neighbourhood of a point z∈X/Rz \in X/R, and (Wk)(W_k) is a sequence of sets belonging to the base (Un)(U_n), contained in φ−1(V)‾\overline{\varphi^{-1}(V)} and covering φ−1(z)‾\overline{\varphi^{-1}(z)}, show that there is a finite number of indices kk such that the union of the φ−1(Wk)‾\overline{\varphi^{-1}(W_k)} is a neighbourhood of zz. Argue by contradiction: if this statement were false we could construct a sequence (γn)(\gamma_n) of distinct points of X/RX/R, tending to zz and such that γn\gamma_n did not belong to the union of the φ(Wk)\varphi(W_k) for k≤nk \leq n; then show that the union of the φ−1(γn)‾\overline{\varphi^{-1}(\gamma_n)} would be closed in XX.]

证明如果假设 RR 是闭集且每个等价类 mod RR 都是紧致的(类似方法),那么同样的结论是有效的。

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Google 翻译生成的粗略草稿,质量较低。术语依照术语表,但句子可能有误;之后会由仔细的译文取代。